Optimal. Leaf size=84 \[ \frac {(d+e x)^2 \left (a+b \sec ^{-1}(c x)\right )}{2 e}-\frac {b d \tanh ^{-1}\left (\sqrt {1-\frac {1}{c^2 x^2}}\right )}{c}-\frac {b e x \sqrt {1-\frac {1}{c^2 x^2}}}{2 c}+\frac {b d^2 \csc ^{-1}(c x)}{2 e} \]
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Rubi [A] time = 0.17, antiderivative size = 84, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 9, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.643, Rules used = {5226, 1568, 1396, 1807, 844, 216, 266, 63, 208} \[ \frac {(d+e x)^2 \left (a+b \sec ^{-1}(c x)\right )}{2 e}-\frac {b d \tanh ^{-1}\left (\sqrt {1-\frac {1}{c^2 x^2}}\right )}{c}-\frac {b e x \sqrt {1-\frac {1}{c^2 x^2}}}{2 c}+\frac {b d^2 \csc ^{-1}(c x)}{2 e} \]
Antiderivative was successfully verified.
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Rule 63
Rule 208
Rule 216
Rule 266
Rule 844
Rule 1396
Rule 1568
Rule 1807
Rule 5226
Rubi steps
\begin {align*} \int (d+e x) \left (a+b \sec ^{-1}(c x)\right ) \, dx &=\frac {(d+e x)^2 \left (a+b \sec ^{-1}(c x)\right )}{2 e}-\frac {b \int \frac {(d+e x)^2}{\sqrt {1-\frac {1}{c^2 x^2}} x^2} \, dx}{2 c e}\\ &=\frac {(d+e x)^2 \left (a+b \sec ^{-1}(c x)\right )}{2 e}-\frac {b \int \frac {\left (e+\frac {d}{x}\right )^2}{\sqrt {1-\frac {1}{c^2 x^2}}} \, dx}{2 c e}\\ &=\frac {(d+e x)^2 \left (a+b \sec ^{-1}(c x)\right )}{2 e}+\frac {b \operatorname {Subst}\left (\int \frac {(e+d x)^2}{x^2 \sqrt {1-\frac {x^2}{c^2}}} \, dx,x,\frac {1}{x}\right )}{2 c e}\\ &=-\frac {b e \sqrt {1-\frac {1}{c^2 x^2}} x}{2 c}+\frac {(d+e x)^2 \left (a+b \sec ^{-1}(c x)\right )}{2 e}-\frac {b \operatorname {Subst}\left (\int \frac {-2 d e-d^2 x}{x \sqrt {1-\frac {x^2}{c^2}}} \, dx,x,\frac {1}{x}\right )}{2 c e}\\ &=-\frac {b e \sqrt {1-\frac {1}{c^2 x^2}} x}{2 c}+\frac {(d+e x)^2 \left (a+b \sec ^{-1}(c x)\right )}{2 e}+\frac {(b d) \operatorname {Subst}\left (\int \frac {1}{x \sqrt {1-\frac {x^2}{c^2}}} \, dx,x,\frac {1}{x}\right )}{c}+\frac {\left (b d^2\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {1-\frac {x^2}{c^2}}} \, dx,x,\frac {1}{x}\right )}{2 c e}\\ &=-\frac {b e \sqrt {1-\frac {1}{c^2 x^2}} x}{2 c}+\frac {b d^2 \csc ^{-1}(c x)}{2 e}+\frac {(d+e x)^2 \left (a+b \sec ^{-1}(c x)\right )}{2 e}+\frac {(b d) \operatorname {Subst}\left (\int \frac {1}{x \sqrt {1-\frac {x}{c^2}}} \, dx,x,\frac {1}{x^2}\right )}{2 c}\\ &=-\frac {b e \sqrt {1-\frac {1}{c^2 x^2}} x}{2 c}+\frac {b d^2 \csc ^{-1}(c x)}{2 e}+\frac {(d+e x)^2 \left (a+b \sec ^{-1}(c x)\right )}{2 e}-(b c d) \operatorname {Subst}\left (\int \frac {1}{c^2-c^2 x^2} \, dx,x,\sqrt {1-\frac {1}{c^2 x^2}}\right )\\ &=-\frac {b e \sqrt {1-\frac {1}{c^2 x^2}} x}{2 c}+\frac {b d^2 \csc ^{-1}(c x)}{2 e}+\frac {(d+e x)^2 \left (a+b \sec ^{-1}(c x)\right )}{2 e}-\frac {b d \tanh ^{-1}\left (\sqrt {1-\frac {1}{c^2 x^2}}\right )}{c}\\ \end {align*}
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Mathematica [A] time = 0.22, size = 114, normalized size = 1.36 \[ a d x+\frac {1}{2} a e x^2-\frac {b d x \sqrt {1-\frac {1}{c^2 x^2}} \tanh ^{-1}\left (\frac {c x}{\sqrt {c^2 x^2-1}}\right )}{\sqrt {c^2 x^2-1}}-\frac {b e x \sqrt {\frac {c^2 x^2-1}{c^2 x^2}}}{2 c}+b d x \sec ^{-1}(c x)+\frac {1}{2} b e x^2 \sec ^{-1}(c x) \]
Antiderivative was successfully verified.
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fricas [A] time = 0.45, size = 130, normalized size = 1.55 \[ \frac {a c^{2} e x^{2} + 2 \, a c^{2} d x + 2 \, b c d \log \left (-c x + \sqrt {c^{2} x^{2} - 1}\right ) - \sqrt {c^{2} x^{2} - 1} b e + {\left (b c^{2} e x^{2} + 2 \, b c^{2} d x - 2 \, b c^{2} d - b c^{2} e\right )} \operatorname {arcsec}\left (c x\right ) + 2 \, {\left (2 \, b c^{2} d + b c^{2} e\right )} \arctan \left (-c x + \sqrt {c^{2} x^{2} - 1}\right )}{2 \, c^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.68, size = 1555, normalized size = 18.51 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.05, size = 141, normalized size = 1.68 \[ \frac {a \,x^{2} e}{2}+a d x +\frac {b \,\mathrm {arcsec}\left (c x \right ) x^{2} e}{2}+b \,\mathrm {arcsec}\left (c x \right ) x d -\frac {b \sqrt {c^{2} x^{2}-1}\, d \ln \left (c x +\sqrt {c^{2} x^{2}-1}\right )}{c^{2} \sqrt {\frac {c^{2} x^{2}-1}{c^{2} x^{2}}}\, x}-\frac {b x e}{2 c \sqrt {\frac {c^{2} x^{2}-1}{c^{2} x^{2}}}}+\frac {b e}{2 c^{3} \sqrt {\frac {c^{2} x^{2}-1}{c^{2} x^{2}}}\, x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.32, size = 93, normalized size = 1.11 \[ \frac {1}{2} \, a e x^{2} + \frac {1}{2} \, {\left (x^{2} \operatorname {arcsec}\left (c x\right ) - \frac {x \sqrt {-\frac {1}{c^{2} x^{2}} + 1}}{c}\right )} b e + a d x + \frac {{\left (2 \, c x \operatorname {arcsec}\left (c x\right ) - \log \left (\sqrt {-\frac {1}{c^{2} x^{2}} + 1} + 1\right ) + \log \left (-\sqrt {-\frac {1}{c^{2} x^{2}} + 1} + 1\right )\right )} b d}{2 \, c} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.90, size = 77, normalized size = 0.92 \[ \frac {a\,x\,\left (2\,d+e\,x\right )}{2}-\frac {b\,d\,\mathrm {atanh}\left (\frac {1}{\sqrt {1-\frac {1}{c^2\,x^2}}}\right )}{c}+b\,d\,x\,\mathrm {acos}\left (\frac {1}{c\,x}\right )-\frac {b\,e\,x\,\left (\sqrt {1-\frac {1}{c^2\,x^2}}-c\,x\,\mathrm {acos}\left (\frac {1}{c\,x}\right )\right )}{2\,c} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 4.42, size = 104, normalized size = 1.24 \[ a d x + \frac {a e x^{2}}{2} + b d x \operatorname {asec}{\left (c x \right )} + \frac {b e x^{2} \operatorname {asec}{\left (c x \right )}}{2} - \frac {b d \left (\begin {cases} \operatorname {acosh}{\left (c x \right )} & \text {for}\: \left |{c^{2} x^{2}}\right | > 1 \\- i \operatorname {asin}{\left (c x \right )} & \text {otherwise} \end {cases}\right )}{c} - \frac {b e \left (\begin {cases} \frac {\sqrt {c^{2} x^{2} - 1}}{c} & \text {for}\: \left |{c^{2} x^{2}}\right | > 1 \\\frac {i \sqrt {- c^{2} x^{2} + 1}}{c} & \text {otherwise} \end {cases}\right )}{2 c} \]
Verification of antiderivative is not currently implemented for this CAS.
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